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Using Theorem 2.2, prove that the line joining the mid-points of any two sides of a triangle is parallel to the third side. |
Answer» In ∆ABC, D and E are mid-points of AB and AC. ∴ AD = DB AE = EC AB = 2AD AC = 2AE \(\frac{AD}{AB} = \frac{AE}{AC}\) = \(\frac{1}{2}\) As per S.S.S. Postulate. ∆ADE ~ ∆ABC ∴ They are equiangular triangles. ∴ ∠A is common. ∠ADE = ∠ABC ∠ADE = ∠ACE These are pair of corresponding angles ∴ DE || BC |
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