Using two light cords a bob is held in equilibrium at A. The horizontal cord is cut and the bob is allowed to swing as a pendulum. Calculate theratio of the tension in the supporting cord in positionB to that in position A.

Using two light cords a bob is held in equilibrium at A. The horizonta

1.	Using two light cords a bob is held in equilibrium at A. The horizontal cord is cut and the bob is allowed to swing as a pendulum. Calculate theratio of the tension in the supporting cord in positionB to that in position A.
Answer» Solution :RESOLVING the TENSION `T_A` at A into two components `T(A) cos theta`balances MG and `T_(B) sin theta`balances the force F. `T_(A) cos theta = mg`…..(i) At By the weight of the bob is resolved into two components. The component `mg cos theta` balances, the tension `T_(A)` The components mg sin 6 ACTS as the RESTORING force. `T_(B)= mg cos theta`...........(ii) `T_(B)/T_(A) = (mg cos theta)/(mg//cos theta) = cos^(2) theta` `T_(B)/T_(A) = cos^(2) theta`