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Using van der Waals equation calculate the constant 'a' when twomolesof a gasconfined in a four litre flask exerts a pressure of 11.0 atmosphere at a temperature of 300 K. The value of 'b' is 0.05 lit mol^(-1) |
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Answer» Solution :`(P+(an^(2))/(V^(2)))(v-nb)=nRT` or`a=((nRT)/(V-nb)-P)(V^(2))/(n^(2))=((2molxx0.08205" L ATM K"^(-1)" mol"^(-1)xx300" K")/(4 L-2 mol xx0.05" L mol"^(-1))-11" atm")XX((4 L)^(2))/((2 mol)^(2))` |
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