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Usingnewton 's laws calculate the tension acting on the mango haging from a tree |
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Answer» Solution :(i) A suitableinertial coordinatesystemis selectedto analysethe problem.formost of the casewe cantakeEarthas aninertialcoordinatesystem. (ii) Identifythe systemto whichNewton'slawsneedto beapplied. (iii) The freebodydiagram is drawn (IV)Oncethe forcesactingon thesystemareidentifiedand THEFREE bodydiargramisdrawn , applyNewton'ssecondlaw. It the lefthandsideof teh equation, therighthandsideof equation WHICHIS theproductof massandacceleration .Hereacceleratin shouldalsobe in vectornotation. (V )IfAccelerationis giventhen theforcecan becalculated. If theforce is givenaccelerationcan becalculated.  By followingthe abovesteps: The inertialcoordinatesystemon the groundis fixedas shownin the figure.  Theforces actingon themangoare (i) Gravitationalforceexertedby the Earthon themangoactingdownwardsalongnegativey -axis. (ii)tensionactgsupwardsalongpositivey-axis Thefree bodydiagramfor themangois shon in thefigure  heremg isthe magnitudeof the gravitationalforceand `(-hat(j))` representsthe unitvectorin negativey directionSincethe mangois at rest withrespect to ustheaccelerationis ZERO`(vec(a)= 0)` By comparingthe componentson bothsidesof theaboveequationwe get `T- mg = 0` Mass of the mangom= 400gandg=9.8 `ms^(-2)` Tensionactingon themangois`T= 0.4 xx 9.8= 3.92 N` |
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