utes. How long williExample 7: 6 pipes are required to fill a tank in

1.	utes. How long williExample 7: 6 pipes are required to fill a tank in 1 hour 20 minutes. Howtake if only 5 pipes of the same type are used?
Answer» 6pipecanfillatank=60+20=80min5pipescanfillatank=xmin∵Itisininverseproportion6×80=5×xx=56×80x=96minHence,Timetakenby5pipetofilltank=96min plz accept as best 6 pipes = 60min 20min = 80min 5 pipes = x min 680 = 5x x=480/5 =96min Number of pipes and time taken are inversely proportional. That is, if number of pipes decrease then the time increases and vice versa. Time taken by 6 pipes to fill the tank = 1hour 20min = 60+20=80min Let the time taken by 5 pipes by y As they are inversely proportional, 6×80=5×y 6×80/5 = y 96min= y Time taken by 5 pipes to fill the tank= 1hour and 36minutes Read more on Brainly.in - https://brainly.in/question/3150761#readmore 96 min is the correct answer of the given question

utes. How long williExample 7: 6 pipes are required to fill a tank in 1 hour 20 minutes. Howtake if only 5 pipes of the same type are used?

Answer»

6pipecanfillatank=60+20=80min5pipescanfillatank=xmin∵Itisininverseproportion6×80=5×xx=56×80x=96minHence,Timetakenby5pipetofilltank=96min

plz accept as best

6 pipes = 60min 20min = 80min

5 pipes = x min

6*80 = 5*x

x=480/5 =96min

Number of pipes and time taken are inversely proportional.

That is, if number of pipes decrease then the time increases and vice versa.

Time taken by 6 pipes to fill the tank = 1hour 20min = 60+20=80min

Let the time taken by 5 pipes by y

As they are inversely proportional,

6×80=5×y

6×80/5 = y

96min= y

Time taken by 5 pipes to fill the tank= 1hour and 36minutes

Read more on Brainly.in - https://brainly.in/question/3150761#readmore

96 min is the correct answer of the given question