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V= 120 cm O Two concave mirror each of R=40 cm are placedsuch that their principal axisare porallel to each1 cm. Both are at a separation ofConsider the first reflection of Mi. Takingthe location of object asof object as origin. Find thecoordinates of imageotherby100 cm. Consider the​

Answer»

tion:Using MIRROR formula for FIRST reflection: (1/f) = (1/v) + (1/u) ⇒ (1/-20) = (1/v) + (1/-70) ⇒ (1/v) = (1/60) –(1/20) ⇒ v = -30 cm Using mirror formula for first reflection: (1/f) = (1/v) + (1/u) ⇒ (1/-20) = (1/v) + (1/-70) (1/v) = (1/70) – (1/20) = [(2-7)/140] ⇒ v = -(140/5) = -28 cm Height of I2 ⇒ m = (-30/-60) = I2/-1 ⇒ I1 = (1/2) cm Height of first IMAGE from x-axis = 1 + (1/2) = 3/2 cm Height of I2 ⇒ m = (-28/-70) = 2I2/3 ⇒ I2 = [3*28]/[2*70] I2= -0.6 cm co-ordinate of I2= (12 - 0.6)



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