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V=(6x-8xy-8y+6yz) volt. Find force on charge 2C placed at (1,1,1).[Ans:-4 root 35)N​

Answer» 4 √ 35 NExplanation:Given : V = ( 6 x - 8 x y + 8 y + 6 y z )We know : E = - d V / d rNow partially differentiating we get : E_x = 6 - 8 yE_y = - 8 x - 8 + 6 zE_z = 6 yNow at ( 1 , 1 , 1 )E_x = - 2 E_y = - 10 E_z = 6 Now net electric field : E_net = √ ( ( - 2 )² + ( - 10 )² + ( 6 )² ) E_net = √ ( 4 + 100 + 36 )E_net = √ 140 N C⁻¹We are ASKED to find force : We have CHANGE q = 2 CWe know : F = q EPutting values here we get : F = 2 × √ 140 N= > F = 4 √ 35 NHence we get required answer!


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