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(v) MnO_(4)^(2-) to MnO_(4)^(2-)+MnO_(2) . |
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Answer» Solution :`underset(+6)(MnO_(4)^(2-))to underset(+7)(MnO_(4)^(-))+e^(-)` (Oxidation ) …………(1) `underset(+6)(MnO_(4)^(2-)+2e^(-))to underset(+4)(MnO_(2)) ` (Reduction) …………(2) MULTIPLY equation (1) by (2) `2MnO_(4)^(2-) to MnO_(4)^(-)+2e^(-)` …………(3) Add equation (2) and (3) `3MnO_(4)^(2-) to MnO_(2)+2MnO_(4)^(-)` Balance O atoms by adding `H_2O` on the side FALLING SHORT of oxygen atoms `3MnO_(4)^(2-)to MnO_(2)+2MnO_(4)^(-)+2H_(2)O` Balance H atoms by adding `H^(+)` on the side falling short of hydrogen atoms `3MnO_(4)^(2-)+4H^(+)to MnO_(2)+2MnO_(4)^(-)+2H_(2)O`. |
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