व तात कीनिट] हित Catb)n+ Ca-b)y = 2

1.	व तात कीनिट] हित Catb)n+ Ca-b)y = 2
Answer» Here,(a + b)x + (2a - b)y = 21 2x + 3y = 7 A/c to question , infinity many solutions possible , so, (a + b)/2 = (2a - b)/3 = 21/7 (a + b)/2 = 21/7 = 3 (a + b) = 6 ------(1) again,(2a - b)/3 = 21/7 = 3 (2a - b) = 9 --------(2) solve equations (1) and (2) 3a = 15 a = 5 and b = 1 hence, if a = 5 and b = 1 then , infinitely many solutions possible of given equations.

Answer»

Here,(a + b)x + (2a - b)y = 21 2x + 3y = 7 A/c to question , infinity many solutions possible , so, (a + b)/2 = (2a - b)/3 = 21/7

(a + b)/2 = 21/7 = 3

(a + b) = 6 ------(1)

again,(2a - b)/3 = 21/7 = 3

(2a - b) = 9 --------(2)

solve equations (1) and (2)

3a = 15 a = 5 and b = 1

hence, if a = 5 and b = 1 then , infinitely many solutions possible of given equations.

Discussion