InterviewSolution
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InterviewSolution
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V = V2 = V2 = 2V HHE6VR1 = 512AR3 = 12 22R2 = 8.2K*(a) What is the total circuit resistance?(b) What is the ammeter reading?(c) What is the voltmeter reading?(d) What is the potential drop across 5 resistor?+$ Vx &x2X2EB I USIIIE |
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Answer» The circuit can be reduced, step by step, to a single equivalent resistance. The 8 ohm and the 8 ohm are connected in parallel , and so they can be replaced by an equivalent resistor Rp of 4 ohms, using the below equation.Rp= (8+8)(8×8) =4ohmsThis resistor is connected in series with the 4 ohm resistor R1. The total resistance RT of the circuit is thenR t =R 1 +R p =4+4=8ohms.Since the 4 ohm and the 4 ohm are connected in series, they have the same current I1, which must be EQUAL to the current of the BATTERY. Using Ohms LAW we get,I= RV = 88 =1A.Hence, the current flowing through the resistor R1 (4 ohms) is 1A.Now the potential difference across the resistor R1 (4 ohms) is given as follows.V=IR=1×4=4VHence, the potential difference across the resistor R1 (4 ohms) = 4V.Explanation:I hope its right |
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