1.

Value of acceleration due to gravity is 9.8m//sec^(2). Find its value in km//hr^(2).

Answer»

Solution :`n_(1)=n_(2)[(L_(2))/(L_(1))]^(1)[(T_(2))/(T_(1))]^(-2)`.
Given `n_(2)=9.8`
`therefore n_(1)=9.8 [(1M)/(1km)]^(1)[(1 SEC)/(1HR)]^(-2)`
`=9.8[(1m)/(1000m)]^(1)[(1 sec)/(60xx60sec)]^(-2)`
`n_(1)=9.8[(1)/(1000)xx60xx60xx60xx60]`
`n_(1)=98xx36xx36=127008`
`therefore g=127008km//hr^(2)`


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