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Value of acceleration due to gravity is 9.8m//sec^(2). Find its value in km//hr^(2). |
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Answer» Solution :`n_(1)=n_(2)[(L_(2))/(L_(1))]^(1)[(T_(2))/(T_(1))]^(-2)`. Given `n_(2)=9.8` `therefore n_(1)=9.8 [(1M)/(1km)]^(1)[(1 SEC)/(1HR)]^(-2)` `=9.8[(1m)/(1000m)]^(1)[(1 sec)/(60xx60sec)]^(-2)` `n_(1)=9.8[(1)/(1000)xx60xx60xx60xx60]` `n_(1)=98xx36xx36=127008` `therefore g=127008km//hr^(2)` |
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