1.

Value of equilibrium constant `(K_P​)` for a reaction A(g) 2B(g) is 0.0005 atm. What does it indicate ? (I) Products are more stable than reactants. (II) Reactants are very less dissociated. (III) Reactants are more stable than products. (IV) Value of `K_C​` will be less than `K_P`​ at 300 K.A. II and IIIB. III and IVC. II, III and IVD. I, II, III and IV

Answer» Correct Answer - C
Very small value of `K_P`​ indicates that reactants are more stable and very less dissociation.
Unit of `K_P`​ = atm indicates that `Deltan_g`​ = 1 and `K_P`​ is greater than `K_C`


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