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Value of `int_(0)^(pi//2) cos 3t` isA. `(2)/(3)`B. `-(1)/(3)`C. `- (2)/(3)`D. `(1)/(3)` |
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Answer» Correct Answer - B `int_(0)^(pi//2) cos 3t dt=[(sin 3t)/(3)]_(0)^(pi//2)` `= (1)/(3) [-1-0]=(-1)/(3)`. |
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