1.

Value of K_(p) in the reaction MgCO_(3(s))hArrMgO_((s))+CO_(2(g)) is

Answer»

`K_(p)=P_(CO_(2))`
`K_(p)=P_(CO_(2))xx(P_(CO_(2))xxP_(MgO))/(P_(MgCO_(3)))`
`K_(p)=(P_(CO_(2))xxP_(MgO))/(P_(MgCO_(3)))`
`K_(p)=(P_(MgCO_(3)))/(P_(CO_(2))xxP_(MgO))`

Solution :In this REACTION gaseous MOLECULE count `MgCO_(3)to MgO_((s))+CO_(2(g))K_(p)=P_(CO_(2))`


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