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Value of limit `lim_(xrarr0^(+))x^(x^(x)).ln(x)` isA. `1`B. `0`C. Does not existsD. `2` |
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Answer» Correct Answer - B `"lt"_(xrarr0^(+)) x^(x^(x)).ln(x)="lt"_(xrarr0^(+)).xln(x)` `="lt"_(xrarr0^(+))xln(x).exp.(ln(x^(x^(x)-1))` `"lt"_(xrarr0^(+))xln(x).exp.((x^(x)-1)ln(x))` `="lt"_(xrarr^(0^(+))xln(x).exp((e^(xIn(x))-1).ln(x))` `"lt"_(xrarr0^(+))xln(x).exp.(((e^(xIn(x))-1)/(xIn(x))).xln^(2)(x))` `ouarr.xp(1.0uarr)` `ouarr.1=0` (using `"lt"_(xrarr0^(+))x^(m).In(x)=0` for `mgt0`) |
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