1.

Vander Waal's constant 'b' of a gas is 125.57 centilite/mol. The nearest distance between the centes of the two molecules is "x" xx 10^(-7)cm

Answer»

SOLUTION :1 `1.6xx10^(-7) cm`
`b=N_(A)xx4xx4//3pi r^(3)` `125.57xx10^(-2)xx1000=6.023xx10^(23)xx4xx4//3xx3.14^(3)`
`r^(3) =(125.57xx10xx3)/(6.023xx10^(23)xx4xx4xx3.14)`
`r=5xx10^(-8) cm`
So collision diameter (nearest possible DISTANCE) `=1.0xx10^(-7) cm`
x=1


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