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Vapour density of a volatile substance is ` 4 (O_(2)= 1). ` Its molecular weight would be A. 8B. 2C. 64D. 128 |
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Answer» Correct Answer - D If the vapour density of `O_(2)` is taken as 1 , then V.D of the O.C . = 4 . As the actual V.D of `O_(2) = 32//2 = 16` `therefore` Actual V.D of O.C = `16 xx 4 = 64`. Hence molecular mass of O.C = `2 xx 64 = 128` |
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