1.

Vapour density of PCl_(5) is 104.16 but when heated at 230^(@)C its vapour density is reduced to 62. The degree of dissociation of PCl_(5) at this temperature will be

Answer»

`6.8%`
`68%`
`46%`
`64%`

Solution :`PCl_(5)iffPCl_(3)+Cl_(2)`
`{:("INITIAL",c,0,0),("Al EQM.",c(1-alpha),calpha,calpha):}`
Total MOLES at eq = `c(1-alpha)+calpha+calpha=c(1+alpha)`
For a reaction at equilibrium, vapour density is inversely proportional to the number of moles, therefore,
`("Total moles at eq.")/("Initial total moles")=("Vapour density initial")/("Vapour density at eq.")`
or `(c(1+alpha))/(c)=(D)/(d),or1+alpha=(D)/(d),alpha=(D)/(d)-1`
`alpha=(D-d)/(d)=(104.16-62)/(62)=0.68=68%`


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