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Vapour pressure of an aqueous solution of glucose is 750 mm of Hg at 373 K. Calcualte the molality and mole fraction of solution?

Answer»


Solution :`(760-750)/(760)=x_(2)or x_(2)=(10)/(760)." But "x_(2)=(n_(2))/(n_(1))." Total CALCULATE molality, calculate "n_(2)" when "w_(1)=1000G, i.e., n_(1)=1000//18" moles"`
Thus, `n_(2)=(10)/(760)xx(1000)/(18)=0.73`, i.e., molality = 0.73.


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