1.

Vapour pressure of waterat 20^(@)C is 17.5 mm Hg. Calculate the vapour pressure of the soution at 20^(@)C and 15 g of glucose (molar mass= 180 g mol^(-1)) is dissolved in 150 g of water.

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Solution :ACCORDING to Raoult's Law
`(P_(A)-P_(S))/P_(S)=n_(B)/n_(A)=W_(B)/M_(B)xxM_(A)/W_(A)`
`(17.5 mm-P_(S))/P_(S)=((15g))/((180" G mol"^(-1)))xx((18" g mol"^(-1)))/((150g))=0.01`
`(17.5mm)/P_(S)-1=0.01 or ((17.5mm))/P_(S)=1.01`
`P_(S)=((17.5"pm"))/1.01=17.326mm.`


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