Saved Bookmarks
| 1. |
Vapour pressures of benzene and toluene in a mixute at 50^(@)C are given in mm by P=179 X_(B)+92 where X_(B) is the mole fraction of benzene. Calculate. (a) Vapour pressures of pure benzene and toluene at 50^(@)C. |
|
Answer» Solution :For pure BENZENE, `X_(B)=1`. HENCE `P_(B)^(@)=179+92="271mm"` For pure TOLUENE, `X_(B)=0.` Hence `P_(T)^(@)=179xx0+92 = "92 mm"` |
|