Vapour presure of chloroform (CHCI_(3)) and dichloromethane (CH_(2)CI_(2)) at 25^(@)C are 200 mm Hg and 41.5 mm Hg respectively Vapour pressure of the solution obtained by mixing 25.5 g or CHCI_(3) and 40g of CH_(2)CI_(2) at the same temperature will and 40 g of CH_(2)CI_(2) at the same temperature will be (("Molecular mass of" CHCI_(3) = 119.5 u and molecular mass 0 CH_(2)CI_(2) = 85 u)

Vapour presure of chloroform (CHCI_(3)) and dichloromethane (CH_(2)CI_

1.	Vapour presure of chloroform (CHCI_(3)) and dichloromethane (CH_(2)CI_(2)) at 25^(@)C are 200 mm Hg and 41.5 mm Hg respectively Vapour pressure of the solution obtained by mixing 25.5 g or CHCI_(3) and 40g of CH_(2)CI_(2) at the same temperature will and 40 g of CH_(2)CI_(2) at the same temperature will be (("Molecular mass of" CHCI_(3) = 119.5 u and molecular mass 0 CH_(2)CI_(2) = 85 u)
Answer» 173.9 mm Hg 615.0 mm Hg 347.9 mm Hg 90.64 mm Hg Solution :`p^(o)CHCI_(3) = 200 mm Hg, p^(o)CH_(2)CI_(2) = 41.5 mm Hg` `"Moles of "CHCI_(3) "Mass"/"Molecular mass"=25.5/119.5 = 0.213` `"Moles of " CH_(2)CI_(2) = 40/85 = 0.470` `X_(CHCI_(3)) = 0.213/(0.213 + 0.470) = 0.31` `X_(CH_(2)CI_(2))= 0.470/(0.213 + 0.470)=0.69` `P_(T) = P^(o_(CHCI_(3))) X_(CHCI_(3)) + P^(o_(CH_(2)CI_(2)))X_(CH_(2)CI_(2)` `P_(T) = 200 xx 0.31 + 41.5 xx 0.69 ` `P_(T) = 62 + 28.63 = 90.63`