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`vecP,vecQ,vecR,vecS` are vector of equal magnitude. If `vecP+vecQ-vecR=0` angle between `vecP` and `vecQ` is `theta_(1)`.If `vecP+vecQ-vecS=0` angle between `vecP` and `vecS` is `theta_(2)`.The ratio of `theta_(1)` to`theta_(2)` isA. `1:2`B. `2:1`C. `1:1`D. `1:sqrt3` |
Answer» Correct Answer - B `vecP+vecQ=vecR,vecP+vecQ=vecS`, `theta_(2)= "tan"^(-1)(Qsintheta_(1))/(P+Qcostheta_(1)),theta_(1)/theta_(2)=?` |
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