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Vector `vec(A)` is 2`cm` long and is `60^(@)` above the x-axis in the first quadrant. Vector `vec(B)` is `2 cm` long and is `60^(@)` below the x-axis in the fourth quadrant. The sum `vec(A)+vec(B)` is a vector of magnitudes |
Answer» `vecR=vecA+vecB` `vecR=2cos 60^(@)hati+2sin60^(@)hatj+2cos 60^(@)hati-2sin60^(@)hatj` `vecR=4cos 60^(@)hati` `therefore R=2cm`, along x-axis |
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