Vector vecA is 2cm long and is 600 above the x-axis in the first quadrant, vector vecB is 2cm long and is 600 below the x-axis in the fourth quadrant. Find vecA+vecB.

Vector vecA is 2cm long and is 600 above the x-axis in the first quadr

1.	Vector vecA is 2cm long and is 600 above the x-axis in the first quadrant, vector vecB is 2cm long and is 600 below the x-axis in the fourth quadrant. Find vecA+vecB.
Answer» Solution : `VECR=vecA+vecB` `vecR = 2cos60^(0)hat(i)+2sin60hat(J)+2cos60hat(i)-2sin60hat(j)` `vecR = 4cos60hat(i) = 2hat(i)` `:.2cm, ALONG x-axis