Vectors →C and →D have magnitudes of 3 and 4 units respectively. W

1.	Vectors →C and →D have magnitudes of 3 and 4 units respectively. What is the angle between the directions of →C and →D if the magnitude of vector product →C×→D is x and y respectively?(x) 0 (y) 12 units(i) 0 (ii)π2 (iii)π3 (iv) π4
Answer» Vectors $\to C$ and $\to D$ have magnitudes of 3 and 4 units respectively. What is the angle between the directions of $\to C$ and $\to D$ if the magnitude of vector product $\to C \times \to D$ is x and y respectively? (x) 0 (y) 12 units (i) 0 (ii) $\frac{π}{2}$ (iii) $\frac{π}{3}$ (iv) $\frac{π}{4}$

Vectors →C and →D have magnitudes of 3 and 4 units respectively. What is the angle between the directions of →C and →D if the magnitude of vector product →C×→D is x and y respectively?(x) 0 (y) 12 units(i) 0 (ii)π2 (iii)π3 (iv) π4

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Vectors $\to C$ and $\to D$ have magnitudes of 3 and 4 units respectively. What is the angle between the directions of $\to C$ and $\to D$ if the magnitude of vector product $\to C \times \to D$ is x and y respectively?

(x) 0 (y) 12 units

(i) 0 (ii) $\frac{π}{2}$ (iii) $\frac{π}{3}$ (iv) $\frac{π}{4}$

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Vectors →C and →D have magnitudes of 3 and 4 units respectively. What is the angle between the directions of →C and →D if the magnitude of vector product →C×→D is x and y respectively?(x) 0 (y) 12 units(i) 0 (ii)π2 (iii)π3 (iv) π4

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