InterviewSolution
Saved Bookmarks
| 1. |
Velocity and acceleration vector of a charged particle moving in a magnetic field at some instant are `vecv=3hati+4hatj and veca=2hati+xhatj`. Select the correct options.A. `x=-1.5`B. `x=3`C. Magnetic field is along z-directionD. Kinetic energy of the particle is constant |
|
Answer» Correct Answer - (a,b,c) As `vecFbot vecv, so vecF.vecv=0 implies mveca.vecv=0` `implies m(2hati+xhatj).(3hati+4hatj)=0` `implies 6+4x=0 implies x=-1.5` Let the magnetic field is `vecB=ahati+bhatj+chatk`, then from `vecF=qvecv xx vecB` `implies m(2hati+xhatj)=q(3hati+4hatj)xx(ahati+bhatj+chatk)` `implies 2mhati-1.5mhatj=q(3bhatk-3chatj-4ahatk+4chati)` `4c=2m implies c!=0` `3b-4a=0 implies b=4/3a` |
|