Velocity and accleration of a particle at time t=0"are" vecu=(2hati+3hatj)m//s"and"veca=(4hatI+2hatj)m//s^(2)respectively. Find the velocity and displacement of the particle at t=2s.

Velocity and accleration of a particle at time t=0"are" vecu=(2hati+3h

1.	Velocity and accleration of a particle at time t=0"are" vecu=(2hati+3hatj)m//s"and"veca=(4hatI+2hatj)m//s^(2)respectively. Find the velocity and displacement of the particle at t=2s.
Answer» SOLUTION :Here , acceleration `veca=(4hati+2hatj)m//s^(2)`Is constant . So , we can apply `VECV=vecu+vecat"and"vecs=vecut+1/2vecat^(2)` Sustituting tha proper values, we get `vecv=(2hati+3hatj)+(2)(4hati+2hatj)=(10hati+7hatj)m//s`and `vecs=(2)(2hati+3hatj)+1/2(2)^(2)(4hati+2hatj)=(12hati+10hatj)m` THEREFORE , velocity and displacement of particle at `t=2s `are `(10hati+7hatj)m//s`and`(12hati+10hatj)m`respectively.