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Velocity of a particle at time t is given by v=at+(b)/(t+c)a,b, care constant. The dimension of a b, c will be ......

Answer»

`L^(2),T and LT^(-2)`
`LT^(2),LT and L`
`L,LT and T^(2)`
`LT^(2), L and T`

SOLUTION :`v=at+(b)/(t+C)`
Hence both term on RIGHT hand SIDE should have dimension of velocity.
`:.v=at`
`:.a=(v)/(t)`
`:.[a]=([v])/([t])`
`=(LT^(-1))/(T)`
`=LT^(-2)`By homogeneity indicate,
and `v=(b)/(t+c)=(b)/(t) "" t+c`(has dimension of time)
`:.b=vt "" c=t`
`:.[b]=[v][t] :. [c]=[t]`
`=(LT^(-1))(T) "" :. c=T`
`=L`
`:.[a],[b],[c]=LT^(-2), L and T`


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