Velocity of a particle moving in a stright line varies with its displacement as v=(sqrt(4+4s))m//s. Find its displacement in the first 2 seconds of its motion

Velocity of a particle moving in a stright line varies with its displa

1.	Velocity of a particle moving in a stright line varies with its displacement as v=(sqrt(4+4s))m//s. Find its displacement in the first 2 seconds of its motion
Answer» Solution :SQUARING the GIVEN equation, we GET `V^(2)=4+4s` Now , comparing it with `v^(2)=u^(2)+2as` we get, `u=2m//s "and" a=2m//s^(2)` THEREFORE , Dispalcement `t=2s`is `s=ut+1/2at^(2)"or"s=(2)(2)+1/2(2)(2)^(2)"or"s=8m`