1.

Velocity of a particle varies with time as `v=athati+2ht^(2)hatj`. If the particle starts from point `(0,c)`, the trajectory of the particle isA. `y=(bx^(3//2))/a+c`B. `y=(4sqrt(2)b)/3(x/a)^(3//2)+c`C. `y=(4sqrt(2)b)/3(x/a)^(3//2)-c`D. `y=(bx^(3//2))/a-c`

Answer» Correct Answer - A


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