

InterviewSolution
Saved Bookmarks
1. |
Velocity of a particle varies with time as `v=athati+2ht^(2)hatj`. If the particle starts from point `(0,c)`, the trajectory of the particle isA. `y=(bx^(3//2))/a+c`B. `y=(4sqrt(2)b)/3(x/a)^(3//2)+c`C. `y=(4sqrt(2)b)/3(x/a)^(3//2)-c`D. `y=(bx^(3//2))/a-c` |
Answer» Correct Answer - A |
|