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Velocity of a projectile at height `15 m` from ground is `v=(20hati+10hatj)m//s`. Here `hati` is in horizontal direction and `hatj` is vertically upwards. Then Speed with which particle is projected from ground is……… m/sA. 30B. `20sqrt(2)`C. `sqrt(20)`D. `3sqrt(40)` |
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Answer» Correct Answer - B |
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