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Velocity of particle of mass 2kg varies with time t accoridng to the equation `vecv=(2thati+4hatj)ms^(-1)`. Here t is in seconds. Find the impulse imparted to the particle in the time interval from t=0 to t=2s. |
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Answer» Impulse=Change in momentum`=m(vecv_(2)-vecv_(1))` `=2xx[(4hati+4hatj)-(4hatj)]=8hati kgms^(-1)` |
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