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Velocity-time graph for the motion of a certain body is shown in Fig. Explain the nature of this motion. Find the initial velocity and acceleration and write the equation for the variation of displacement with time. What happens to the moving body at point B? How does the body move after this moment ?

Answer» <html><body><p></p>Solution :<img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_A_C03_SLV_022_S01.png" width="80%"/> <br/> The <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> –time graph is a <a href="https://interviewquestions.tuteehub.com/tag/straight-633156" style="font-weight:bold;" target="_blank" title="Click to know more about STRAIGHT">STRAIGHT</a> <a href="https://interviewquestions.tuteehub.com/tag/line-1074199" style="font-weight:bold;" target="_blank" title="Click to know more about LINE">LINE</a> with=ve slope. The motion is <a href="https://interviewquestions.tuteehub.com/tag/uniformly-720232" style="font-weight:bold;" target="_blank" title="Click to know more about UNIFORMLY">UNIFORMLY</a> retarding up to point B and there after uniformly accelerated up to C. <br/> At point B the body stops and then its direction of velocity reversed. <br/> The initial velocity at point A is `v_0="7 ms"^<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>` <br/> `a=(v_f-v_0)/(triangle t)=(0-7ms^(-1))/(11s)=(-7)/(11)ms^(-2)=0.64ms^(-2)` <br/>The equation of motion for this body which gives variation of displacement with time is<br/> `S=7t-1/2 0.64t^(2)=7t-0.32t^2`.</body></html>


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