ven figure. ABC is a triangle with BD and CE perpendicularand AB respe

1.	ven figure. ABC is a triangle with BD and CE perpendicularand AB respectively, such that BD = CE. Prove thatIn the given figure10 AC and ABBCD = ACBEBin the mid points of sides AB, BC
Answer» it is given that BD is perpendicular to AC and CE is perpendicular to a b now in angle abc and ABC be equal to CD given യുവർ ടെസ്റ്റ്‌ 1+1=2 അതുപോലെ നൂക്കുംനെ Given: In ∆ABC, BD and CE perpendicular to AC and AB , respectively. And, BD = CE To Prove: ∆BCD is congruence to ∆CBE. Proof: In ∆BCD and ∆CBE, <BDC = <CEB = 90° BD = CE [Given] BC = BC [Common side]Therefore, by RHS congruency rule∆BCD is congruent to ∆CBE.

ven figure. ABC is a triangle with BD and CE perpendicularand AB respectively, such that BD = CE. Prove thatIn the given figure10 AC and ABBCD = ACBEBin the mid points of sides AB, BC

Answer»

it is given that BD is perpendicular to AC and CE is perpendicular to a b now in angle abc and ABC be equal to CD given

യുവർ ടെസ്റ്റ്‌ 1+1=2 അതുപോലെ നൂക്കുംനെ

Given: In ∆ABC, BD and CE perpendicular to AC and AB , respectively. And, BD = CE

To Prove: ∆BCD is congruence to ∆CBE.

Proof: In ∆BCD and ∆CBE, <BDC = <CEB = 90° BD = CE [Given] BC = BC [Common side]Therefore, by RHS congruency rule∆BCD is congruent to ∆CBE.