1.

ven figure, find the measure of ZCAB, ZABC, A9. CABC, ZACB.105°Dand win the.

Answer»

Angle BAC = 45angle ACB = 75nowangle B + 75+45= 180Angle B = 180-120° = 60

Angle BAC = 45; Angle ACB = 75; Angle B +75 + 45 =180;; Angle B = 180 - 120=60

Angle BAC = 45°Angle ACB = 75°Then,Angle B + 75+45 = 180 (linear pair)Angle B = 180-120=60

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ans=1) angle CAB = angle FAE =45°(Vertic. opp.)3) Now in triangle ABCACB = (180-105)°=75°2) We now that the sum of triangle=ABC+BAC+ACB=180°=ABC+45°+75°=180°=ABC=180°-120°=60°

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