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Verify (a+b+c)³ -a³-b³-c³ =3(a+b) (b+c) (c+a)

Answer» Prove that (a +b +c)3\xa0-a3\xa0-b3\xa0– c3\xa0=3(a +b)(b +c)(c +a). Solution to\xa0(a +b +c)3\xa0-a3\xa0-b3\xa0– c3\xa0=3(a +b)(b +c)(c +a)


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