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Verify Lagrange's Mean Value Theorem in interval [0,4), where function f(x) = (x - 1) (x - 2) (x - 3). |
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Answer» Given function f(x) = (x - 1) (x - 2) (x - 3) Hence, f(a) = (-1) (-2) (-3) = 6 ∴ f(0) = 6 ∵ Given function is polynomial Hence function is. (i) Continuous in closed interval (0,4) (ii) Differentiable in open interval (0, 4) |
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