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Verify Rolles theorem for the function f(x)= x2 + 2x – 8, x ∈ [-4, 2] |
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Answer» f (x) = x2 + 2x – 8 1. f(x) being a polynomial function it is continuous on (-4, 2) 2. Also f1 (x) = 2x + 2 hence derivable on (-4, 2) 3. f(-4) = (-4)2 + 2(-4) - 8 = 0 f(2) = 22 + 2(2) - 8 = 0 ∴ f(-4) = f(2) ∴ All three conditions of Rolle’s theorem are verified. f1(c) = 0 f1 (c) = 2c + 2 ⇒ 0 = 2c + 2 ⇒ c = -1 ∈(-4, 2) |
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