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Verify that the given function (explicit or implicit) isa solution of the correseponding differential equation : y = e^x + 1: y'' - y' = 0 |
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Answer» SOLUTION :` y = e^x + 1` `RARR y. = e^x` `rArr y.. = e^x = y.` `THEREFORE y.. - y. = 0 ` Therefore, `y = e^x + 1` is a solution of y.. - y. = 0 |
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