1.

Verify that (x – 1) is a factor of the polynomial x3 + 4x – 5.

Answer»

Here, p(x) = x3 + 4x – 5 

Substituting x = 1 in p(x), we get 

p(1) = (1)3 + 4(1) – 5 

= 1 + 4 – 5 

P(1) = 0 

∴ By remainder theorem, 

Remainder = 0 

∴ (x -1) is the factor of x3 + 4x – 5.


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