Saved Bookmarks
| 1. |
Verify the law of reciprocal proportions from the following data : KCl contains 52.0 % potassium , KI contains 23.6 % potassium while Icl contains 78.2 % iodine. |
|
Answer» Solution :Let 1 g of potassium (K) be the FIXED WEIGHT In KCl, 52.0 g of K are COMBINED with Cl = 48.0 g 1.0 g of K are combined with `Cl = (48.0)/(52.0)g = 0.092 g` In KI, 23.6 g of K are combined with `I = 76.4 g` 1.0 g of K is combined with `I = (76.4)/(23.6)g = 3.24 g` Ratio by weight of I and Cl combined with 1.0 g of K in the two halides `= (3.24)/(0.92)` In ICI, ratio by weight of I and Cl `= (78.2)/(21.8)` COMPARING the two ratios : `(3.24)/(0.92):(78.2)/(21.8)or 3.52:3.59` Since the two ratios are nearly the same, this verifies the Law of Reciprocal Proportions.
|
|