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Verify whether `x = 2` is a solution of `2x^(2) + x - 10 =0` |
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Answer» On substituting `x = 2`, in `2x^(3) + x - 10`, we get `2(2)^(2) + 2 - 10= 10 - 10= 0`. `:. 2` is a solution (or) root of `2x^(2) + x - 10 = 0`. |
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