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Vessel A contains an ideal gas at a pressure `5xx10^(5)` Pa and is connected with a heat source which maintains its temperature at `300 K`. Another vessel B which has four time greater inner volume contains the same gas at a pressure `10^(5)` Pa and is connected to a heat source which maintains its temperature at `400 K`. What will be the pressure of entire system if two vessels are connected by a narrow tube tap:-A. `10^(5)Pa `B. `2xx10^(5)Pa`C. `4xx10^(5)Pa`D. `5xx10^(5)Pa` |
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Answer» Correct Answer - B `(P_(A)V_(A))/(RT_(A))+(4P_(B)V_(A))/(RT_(B)) = (pV_(A))/(RT_(A))+(4pV_(A))/(RT_(B))` `(p_(A))/(T_(A))+(4p_(B))/(T_(B))=(p)/(T_(A))+(4p)/(T_(B))` `(5xx10^(5))/(300)+(4xx10^(5))/(400) = (p)/(300)+(4p)/(400)` `((20+12)xx10^(5))/(1200) = (4p+12p)/(1200)` `32xx10^(5) = 16p` `p = 2xx10^(5) N//m^(2)` |
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