(vi) Five years hence, the age of Jacob will be three times that of hi

1.	(vi) Five years hence, the age of Jacob will be three times that of his son. Five yearsago, Jacob's age was seven times that of his son. What are their present ages?2 Vliminntion
Answer» Solution:Let us assume Jacob’s current age is x and his son’s current age is y. Five years hence, Jacob’s age = x + 5 and his son’s age = y + 5 As per question; x + 5 = 3(y + 5) Or, x + 5 = 3y + 15 Or, x = 3y + 15 – 5 = 3y + 10 Five years ago, Jacob’s age = x – 5 and his son’s age = y – 5 As per question; x – 5 = 7(y – 5) Or, x – 5 = 7y – 35 Or, x = 7y – 35 + 5 = 7y – 30 Substituting the value of x from first equation in this equation, we get; 3y + 10 = 7y – 30 Or, 3y + 10 + 30 = 7y Or, 7y – 3y = 40 Or, 4y = 40 Or, y = 10 Substituting the value of y in first equation, we get; x = 3y + 10 Or, x = 3 x 10 + 10 = 40 Hence, Jacob’s age = 40 years and son’s age = 10 years

(vi) Five years hence, the age of Jacob will be three times that of his son. Five yearsago, Jacob's age was seven times that of his son. What are their present ages?2 Vliminntion

Answer»

Solution:Let us assume Jacob’s current age is x and his son’s current age is y.

Five years hence, Jacob’s age = x + 5 and his son’s age = y + 5

As per question;

x + 5 = 3(y + 5)

Or, x + 5 = 3y + 15

Or, x = 3y + 15 – 5 = 3y + 10

Five years ago, Jacob’s age = x – 5 and his son’s age = y – 5

As per question;

x – 5 = 7(y – 5)

Or, x – 5 = 7y – 35

Or, x = 7y – 35 + 5 = 7y – 30

Substituting the value of x from first equation in this equation, we get;

3y + 10 = 7y – 30

Or, 3y + 10 + 30 = 7y

Or, 7y – 3y = 40

Or, 4y = 40

Or, y = 10

Substituting the value of y in first equation, we get;

x = 3y + 10

Or, x = 3 x 10 + 10 = 40

Hence, Jacob’s age = 40 years and son’s age = 10 years