1.

Voltage standing wave pattern in a impedance 50Ω and a resistive load is shown in the figure.The value of the load resistance is(a) 50Ω (b) 200Ω (c) 12.5Ω (d) 0Ω

Answer»

(c) 12.5Ω

VSWR (S) = \(\frac{V_{max}}{V_{min}}\) = \(\frac41\)

S = 4

Zmax = Z0S

Zmin \(\frac{Z_0}S\)

As minima is at load

ZL =  Zmin \(\frac{Z_0}S\)

ZL\(\frac{50}4\) = 12.5 Ω



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