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Voltage standing wave pattern in a impedance 50Ω and a resistive load is shown in the figure.The value of the load resistance is(a) 50Ω (b) 200Ω (c) 12.5Ω (d) 0Ω |
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Answer» (c) 12.5Ω VSWR (S) = \(\frac{V_{max}}{V_{min}}\) = \(\frac41\) S = 4 Zmax = Z0S Zmin = \(\frac{Z_0}S\) As minima is at load ZL = Zmin = \(\frac{Z_0}S\) ZL = \(\frac{50}4\) = 12.5 Ω |
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