Volume occupied by one molecule of water (density "1 g cm"^(-3)) is :

1.	Volume occupied by one molecule of water (density "1 g cm"^(-3)) is :
Answer» `3.0 xx 10^(-23) cm^(3)` `5.5 xx 10^(23) cm^(3)` `9.0 xx 10^(-23) cm^(3)` `6.023 xx 10^(-23) cm^(3)` SOLUTION :MASS of ONE molecule of water `= ((18g))/(6.022xx10^(23))=3xx10^(-23)g` Since density of water is 1g `:.` Volume occupied by one molecule of water `= 3 xx 10^(-23)` CC.

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