1.

Volume occupied by one molecule of water (density =1g//cm^(3)) is:

Answer»

`3XX10^(-23)cm^(3)`
`5.5xx10^(-23)cm^(3)`
`9xx10^(-23)cm^(3)`
`6.023xx10^(-23)cm^(3)`

Solution :MASS of one molecule`=(18)/(6.023xx10^(23))g`
`=2.98xx10^(-23)g`
Volume of one molecule `=(M)/("DENSITY")=(2.98xx10^(-23))/(1)cm^(3(`
`=3xx10^(-23)cm^(3)`


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