Volume occupied by one molecule of water(density 1g cm-3) is(A) 9.0x10

1.	Volume occupied by one molecule of water(density 1g cm-3) is(A) 9.0x10-23 cm3 (B) 6.023x1023cm3(C) 3.0x1025 cm3 (D) 5.5x10-23 cm324.IAIPMT 2008]23m3
Answer» 6.02210^23 molecules=18 gm of water Therefore,1 molecule=18/6.02210^23 gm of. Water =3.010^-23gm of water We know, density=mass/volume Volume=mass/density =3.010^-23gm/1gm cm^-3 =3.0*10^-23 cm^3

Volume occupied by one molecule of water(density 1g cm-3) is(A) 9.0x10-23 cm3 (B) 6.023x1023cm3(C) 3.0x1025 cm3 (D) 5.5x10-23 cm324.IAIPMT 2008]23m3

Answer»

6.022*10^23 molecules=18 gm of water

Therefore,1 molecule=18/6.022*10^23 gm of. Water

=3.0*10^-23gm of water

We know, density=mass/volume

Volume=mass/density

=3.0*10^-23gm/1gm cm^-3

=3.0*10^-23 cm^3