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Volume occupied by one molecule of water (density `"1 g cm"^(-3)`) is :A. `3.0 xx 10^(-23) cm^(3)`B. `5.5 xx 10^(23) cm^(3)`C. `9.0 xx 10^(-23) cm^(3)`D. `6.023 xx 10^(-23) cm^(3)` |
Answer» Correct Answer - A Mass of one molecule of water `= ((18g))/(6.022xx10^(23))=3xx10^(-23)g` Since density of water is 1g `:.` Volume occupied by one molecule of water `= 3 xx 10^(-23)` cc. |
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